Answer:
y = x² − 6x − 27
Step-by-step explanation:
To distribute, you can use something called FOIL. It stands for First, Outer, Inner, Last.
First, multiply the First term in each factor.
x · x = x²
Now multiply the Outer terms in each factor.
x · 3 = 3x
Next multiply the Inner terms in each factor.
-9 · x = -9x
Finally, multiply the Last terms in each factor.
-9 · 3 = -27
Add them all up:
x² + 3x − 9x − 27
x² − 6x − 27
Width = W
Length = 3 times w = 3W
Area = length x width = 3W * W = 3W^2
Answer:
No he is not lol 16÷4=4, To buy 10, 10×4=40. 40-35=5 he needs 5 dollars more
<h3>
Answer: 375</h3>
=========================================
Work Shown:
a = 300 = first term
r = 60/300 = 0.2 = common ratio
We multiply each term by 0.2, aka 1/5, to get the next term.
Since -1 < r < 1 is true, we can use the infinite geometric sum formula below
S = a/(1-r)
S = 300/(1-0.2)
S = 300/0.8
S = 375
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As a sort of "check", we can add up partial sums like so
- 300+60 = 360
- 300+60+12 = 360+12 = 372
- 300+60+12+2.4 = 372+2.4 = 374.4
- 300+60+12+2.4+0.48 = 374.4+0.48 = 374.88
and so on. The idea is that each time we add on a new term, we should be getting closer and closer to 375. I put "check" in quotation marks because it's probably not the rigorous of checks possible. But it may give a good idea of what's going on.
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Side note: If the common ratio r was either r < -1 or r > 1, then the terms we add on would get larger and larger. This would mean we don't approach a single finite value with the infinite sum.
Answer:
9 students on the committee are males
Step-by-step explanation:
As per the statement:
There are 15 students on a yearbook committee.
⇒Total students on a yearbook committee = 15
⇒
....[1]
It is given that:
40% of the students are females
⇒
Substitute in [1] we have;

Subtract 6 from both sides we have;

Therefore, 9 students on the committee are males