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2 years ago

7

There are 35 boys in the sixth grade. The number of girls in the sixth grade is 42. Lonnie says that means the ratio of number o

f boys to girls in the sixth grade is 5:7. Is Lonnie correct?

1 answer:

lubasha [3.4K]2 years ago

4 0

Answer:

Lonnie is not correct

Step-by-step explanation:

You might be interested in

What is the height of the triangle? A) 17 units B) 34units C) 51units D) 68units <br><br> Help??

drek231 [11]

Answer:

51 units

Step-by-step explanation:

The ratio of the lengths of the sides of a 30-60-90 triangle is

short leg : long leg : hypotenuse = 1 : sqrt(3) : 2

The reason this is relevant here is that in your case, you start with an equilateral triangle, FGH. An equilateral triangle is also equiangular, so all angles are congruent and measure 60 deg.

m<F = m<FGH = m<H = 60 deg

When the height GR is drawn, <FGH is bisected creating two 30-60-90 degree triangles, FGR and HGR.

The altitude GR also bisects side HF, so

HR = FR = (1/2)HF = 17*sqrt(3)

In 30-60-90 degree triangle FRG, the short leg is FR; the long leg is GR; the hypotenuse is FG.

Now we use the ratio of the lengths of the sides of a 30-60-90 degree triangle.

short leg : long leg : hypotenuse = 1 : sqrt(3) : 2

We use only the short leg and long leg parts of the ratios.

17*sqrt(3) : GR = 1 : sqrt(3)

GR * 1 = 17 * sqrt(3) * sqrt(3)

GR = 17 * 3

GR = 51

8 0

3 years ago

Two friends shop for fresh fruit. Jackson buys a watermelon for $8.85 and 3 pounds of cherries. Tim buys a pineapple for $3.35

netineya [11]

Answer:

12.2

Step-by-step explanation:

you add $8.85+$3.35 then that's when you get your answer

for the qustion

8 0

2 years ago

2 divided by 1 third

BARSIC [14]

2 divided by 1 third

2 divided by 1/3

always flip over the second fraction when dividing

2*3/1=6

6/1=6

answer:

6

5 0

2 years ago

Is the triangle a right triangle? Explain.

Eddi Din [679]

Answer:

The triangle is not a Right Triangle because the two acute angles aren't exactly 45 degrees.

Step-by-step explanation:

4 0

3 years ago

If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.

Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

$(10x - 11) = (8x - 20) + 43$

Solve for x

$10x - 11 = 8x - 20 + 43$

$10x - 11 = 8x + 23$

Subtract 8x from both sides

$10x - 11 - 8x = 8x + 23 - 8x$

$2x - 11 = 23$

Add 11 to both sides

$2x - 11 + 11 = 23 + 11$

$2x = 34$

Divide both sides by 2

$\frac{2x}{2} = \frac{34}{2}$

$x = 17$

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0

2 years ago