Answer:
The radius of the circles are 
and 
Step-by-step explanation:
Let
x-----> the radius of larger circle
y----> the radius of smaller circle
we know that
-----> equation A
Remember that
-----> equation B
substitute equation B in equation A and solve for y
Find the value of x
therefore
The radius of the circles are and
Answer:
[ext]T(x) = 2C / Speed[/ext]
Step-by-step explanation:
[ext]Time taken for the Ranger to get to the car = Sum total time taken to travel in the forest and on the road[/ext]
Since [ext]distance of the Ranger to the car = C[/ext]
[ext]Time taken = distance/speed[/ext]
[ext]Total Time taken T(x) = 2 * C / speed[/ext]
T(x) = 2C / speed
<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
Here are the true statements:
The 6 in the third term is a coefficient. It is paired with a variable so it is a coefficient.
The y in the third term is a factor because it is being multiplied by (6x + 7).
The 9 is a constant because it is just a number in the second term.
