Urgent due for tommorow . will mark brainliest and get 50 ptsplz show workings
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Answer:
Jessie scored higher than Reagan.
Step-by-step explanation:
We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.
Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.
For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.
1. <u>Finding z-score for Reagan;</u>
Let X = distribution of SAT scores
SO, X ~ Normal()
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 1000
= standard deviation = 100
Now, Reagan scored 1140 on the SAT, that is;
z-score = = 1.4
2. <u>Finding z-score for Jessie;</u>
Let X = distribution of ACT scores
SO, X ~ Normal()
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 17
= standard deviation = 5
Now, Jessie scored 30 on the ACT, that is;
z-score = = 2.6
This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.
Using it's concept, it is found that the domain for the expressions is, respectively, given by:
It is the <u>set that contains all possible input values</u>.
In a fraction, the denominator cannot be zero, hence:
- The domain of the first two expressions is of
.
- The domain of the last expression is of
.
The third expression can be simplified, as:
(x + 5)/(x + 5) = 1.
The same is true for the fourth, as:
x²/x = 1.
Neither has any restriction, hence their domain is all real numbers, represented by .
More can be learned about the domain of a function at brainly.com/question/25897115