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Vesnalui [34]
3 years ago
7

How do you do the problem 8/2/4-3/1/9

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0

Answer:

if I'm correct it should be

\frac{( \frac{8}{ 2})}{4}   -   \frac{\frac{3}{1} }{9}

1 -  \frac{1}{3}  =  \frac{2}{3}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

8/2/4 means, first you divide 8 by 2 and then you divide the result by 4⠀⠀⠀⠀⠀⠀⠀⠀

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Write an explicit formula for a_na
Masja [62]

Explicit formula for the sequence 29,20,11....... is a_n=38-9n

Given :

term of the sequence 29, 20, 11, ...

We need to find out the formula for the nth term of the given sequence

Lets find out whether the given sequence is arithmetic or geometric

In the given sequence , common difference is 9

20-29=-9\\11-20=-9

we can say difference =-9

General explicit formula

a_n=a_1+(n-1)d

where a1 is the first term

common difference d=-9

substitute the values

a_n=a_1+(n-1)d\\a_n=29+(n-1)(-9)\\a_n=29-9n+9\\a_n=38-9n

Explicit formula for the sequence 29,20,11....... is a_n=38-9n

Learn more :  brainly.com/question/23243640

5 0
3 years ago
What is the predicted difference in sleep between individuals A and B, where individual A has 12 years of education and works 20
kari74 [83]

Answer: The predicted difference in sleep is 1251437 minutes.

Step-by-step explanation:

Since we have given that

Number of years of education = 12 years

Number of minutes a week = 2000

As we have

In case of individual A:

7 days = 2000 minutes

1 year = 365 days = \dfrac{2000}{7}\times 365=104285

12 years = 104285\times 12=1251420\ minutes

In case of individual B:

7 days = 3000 minutes

1 year = 365 days = \dfrac{3000}{7}\times 365=156428

16 years = 156428\times 16=2502857 minutes

So, the predicted difference in sleep between individuals A and B is given by

2502857-1251420\\\\=1251437\ minutes

Hence, the predicted difference in sleep is 1251437 minutes.

7 0
4 years ago
Write a loop that reads positive integers from standard input
igor_vitrenko [27]

Definitely the question is incomplete

Using for loop in java to print positive integers ,let say first 50 integers

So the loop is:

int i ;

for( i= 0; i<= 50; i++ ) {

print (i);

}

The looping will going to start from the 1 and stop to 50

7 0
3 years ago
Write two polynomials whose sum is x to the second power and whose difference is 1
Alex777 [14]

Answer:

Therefore, the  first polynomial is:

Z=\frac{1}{2}x^2+\frac{1}{2}\\

the second polynomial is:

Y=\frac{1}{2}x^2-\frac{1}{2}\\

Step-by-step explanation:

We assume that: Z is first polynomial and Y is second polynomial.

Therefore, we have

Z+Y=x^2\\\\Z-Y=1\\\\\implies Z+Y+Z-Y=x^2+1\\\\2Z=x^2+1\\\\Z=\frac{1}{2}x^2+\frac{1}{2}\\

now, we get

\implies Z+Y-Z+Y=x^2-1\\\\2Y=x^2-1\\\\Y=\frac{1}{2}x^2 -\frac{1}{2}

Therefore, the  first polynomial is:

Z=\frac{1}{2}x^2+\frac{1}{2}\\

the second polynomial is:

Y=\frac{1}{2}x^2-\frac{1}{2}\\

6 0
3 years ago
Which equations are true? A. 10 × 10 × 10 × 10 × 10 = 50 B. 10 × 10 × 10 × 10 × 10 = 105 C. 10 × 10 × 10 × 10 × 10 = 10,000 D. 1
11Alexandr11 [23.1K]

Hi All ^_^

D. 10 × 10 × 10 × 10 × 10 = 100.000

I hope this helps,,

6 0
3 years ago
Read 2 more answers
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