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Elodia [21]
3 years ago
9

Due to the difficult economic times, increased global competition, demand for customization, and increased consumer sophisticati

on, many companies have increased their investment in hiring many employees, and outsource & off shore middle managers.
a. True
b. False
Computers and Technology
1 answer:
Lunna [17]3 years ago
8 0

Answer:

b. False

Explanation:

Difficult economic times, increased global competition, demand for customization, and increased consumer sophistication does not direct companies to hire more employees and outsource middle managers.

Rather, companies tend to invest new technologies, information systems to satisfy the needs in global competition, consumer sophistication and customization.

Middle managers outsourced cannot deal these issues effectively, therefore they need to be company employees.  

In difficult economic times, companies does not want to hire extra employees because of increased cost.

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"Create a Matlab Scrapt that will take the a Matrix A and Matrix B (of AX=B), then calculate the Determinant of Matrix A, Invers
prohojiy [21]

Answer:

see explaination

Explanation:

function [] =

inverse(A,B)

da = det(A);

disp("The det of A is");

disp(da);

inva = inv(A);

disp("The inverse of A is");

disp(inva);

x = inva*B;

disp("The value of X is");

disp(x);

rk = rank(A);

disp("The rank of X is");

disp(rk);

Di = eig(A);

disp("The eigen values of A is");

disp(Di);

[V,Di] = eig(A);

disp("The eigen vectors of A are (Each column represents one column vector)");

disp(V);

end

A = [1,2;4,5];

B = [1,2;4,5];

inverse(A,B);

%ab = [num2str(t)," ",num2str(dx)," ",num2str(dy)];

%disp(ab);

4 0
3 years ago
In addition to format commands that are found in the ribbon, which option is available for more extensive formatting?
eimsori [14]

Answer:

A

Explanation:

5 0
3 years ago
Write the Flowchart to find Even number between 1 to 50<br>​
ASHA 777 [7]

Answer:

See attachment for flowchart

Explanation:

Required

Flowchart to fine even from 1 to 50

The flowchart has been attached.

The rough algorithm (explanation) of the flowchart is as follows.

1. Start

2. Initialize num to 1

3. Check if num is less than or equal to 50

  3.1 If yes

      3.1.1 Check if num is even

      3.1.1.1 If yes

         3.1.1.2 Print num

  3.1.3 Increase num by 1

 3.2 If num is greater than 50

    3.2.1 Stop

4. Goto 3

4 0
3 years ago
Write a SELECT statement that joins the Categories table to the Products table and returns these columns: category_name, product
Sphinxa [80]

Answer & Explanation:

1) Query:

SELECT Product_Name, Category_Name, List_Price

FROM Products AS P JOIN Categories AS C

ON C.Category_ID = P.Category_ID

ORDER BY Category_Name, Product_Name ASC;

2) Query:

SELECT C.Last_Name, C.First_Name, Order_Date, P.Product_Name, Item_Price, Discount_Amount, Quantity

FROM Customers AS C JOIN Orders AS O

ON C.Customer_ID = O.Customer_ID

JOIN Order_Items AS OI

ON O.Order_ID = OI.Order_ID

JOIN Products AS P

ON OI.Product_ID = P.Product_ID

ORDER BY Last_Name, Order_Date, Product_Name;

3) Query:

SELECT Category_Name, Product_ID

FROM Categories LEFT JOIN Products

ON Categories.Category_ID = Products.Category_ID

WHERE Product_ID IS NULL;

4) Query:

SELECT 'SHIPPED' AS Ship_Status, Order_Id, Order_Date

FROM Orders

WHERE Ship_Date IS NOT NULL

UNION

SELECT 'NOT SHIPPED' AS Ship_Status, Order_ID, Order_Date

FROM Orders

WHERE Ship_Date IS NULL

ORDER BY Order_Date;

3 0
3 years ago
URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
3 years ago
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