Answer: Hello your question is poorly written attached below is the well written question
answer:
a) Determine ( compute ) the difference between the max and minimum value. determine the Min and max values using 1.5n comparisons
time efficiency = θ( n )
b) A(n-1) - A(0)
time efficiency = θ( 1 )
Explanation:
a) An unsorted array
To find the maximum and minimum values scan the array of elements , then determine ( compute ) the difference between the max and minimum value. to determine the range. Alternatively determine the Min and max values using 1.5n comparisons
Algorithm's time efficiency = θ( n )
b) A sorted array
To determine the range, we will determine the difference between the first and last element i.e. A(n-1) - A(0)
time efficiency = θ( 1 )
Answer:
Zevzda
Explanation:
Check for yourself if you think i'm wrong
Answer:Conversion disorder
Explanation:Its a mental condition that affects the nervous system.
Answer:
a. 1 is a packet, 2 is data, 3 is a frame.
Explanation:
And what is not mentioned is segment which used TCP/UDP and is part of Transport layer. The packet carries the destination and sender IP address, and is part of the Network Layer. The frame has the Mac address of destination device and senders device and is part of data link layer.
Hence segment has no IP address, hence b. is not correct. Also, data cannot have the IP Address, and Frame has the MAC address, Hence, the above answer. And this arrangement is part of Data Encapsulation.
Also keep in mind data can be anything like a series of bits, or any and it can or not have a header.