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2 years ago

What decimal is bigger 0.33 or 0.34

Mathematics

2 answers:

maxonik [38]2 years ago

8 0

0.33 because it’s closer to one.

Naddika [18.5K]2 years ago

3 0

Answer:

0.34

Step-by-step explanation:

In decimal form, the number closer to one is bigger.

You go by which number in the tenths place is bigger. If they are the same, you move the the next place, which is the hunderth place

For example, how much is more,

33 cents or 34 cents.

A great game to get used to finding which decimal is bigger:

https://www.aaamath.com/dec52_x2.htm

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What is the mean of 18,24,17,21,24,16,29,18

timurjin [86]

Answer:

20.875

Step-by-step explanation:

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2 years ago

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3. The matrices show the enrollment of boys and girls on the basketball, lacrosse, and soccer teams in two towns. Town A Town B

bazaltina [42]

(a). The element a₂₁ is the number of boys enrolled in Lacrosse.

(b). The address is a₁₂.

(c). [196 174]
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(d). The matrix represents the number of boys and girls from towns A and B enrolled in different sports classes.

(e). 1.125 A = [108 90 ]
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3 years ago

A British company is sending you measurements for a table to build in your factory. The table top must be 50 cm x 75 cm. Your ma

Degger [83]

Answer:

<h2>Answer is B!</h2>

Step-by-step explanation:

<h2>Mutiply 0.39*50=19.5</h2><h2>Mutiply 0.39*75=29.25</h2>

4 0

3 years ago

In a paper bag, 7 of the 15 marbles are yellow. In a cloth bag, 2 of the 15 marbles are yellow. If Tim randomly draws one marble

ddd [48]

Answer :

$\frac{7}{15}$ × $\frac{2}{15}$ = $\frac{14}{225}$

Step-by-step explanation:

P( $Event_{1}$ ) = choosing yellow marble from paper bag = $\frac{favourable outcomes}{possible outcomes}$ = $\frac{7}{15}$

P( $Event_{2}$ ) = choosing yellow marble from cloth bag = $\frac{favourable outcomes}{possible outcomes}$ = $\frac{2}{15}$

∵ Resultant outcome is dependent upon both the events and both events are independent from each other, so we can apply intersection rule [ P(A∩B)=P(A)×P(B) ] here

∴ Probability ( Both marbles are yellow) = P( $Event_{1}$ ) × P( $Event_{2}$ ) = $\frac{7}{15}$ × $\frac{2}{15}$

3 0

3 years ago

For each value of x, determine whether it is a solution to x+37 = 46. Is it a solution? X 6 ? х 12 x 9 x 83 ?

Paha777 [63]

1. If x=6, 6+37=?46 43≠46. It isn’t a solution.
2. If x=12, 12+37=?46 49≠46. it’s not a solution.
3. If x=9, 9+37=?46. 46=46. It’s a solution!
4. If x=83, 83+37=?46. 120≠46. Not a solution.

Only x=9 Is a solution.

Hope it helps!

6 0

1 year ago

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