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svetoff [14.1K]
2 years ago
5

Find the missing factor. 200 x ____ = 600 A) 2 B) 3 C) 4 D) 5

Mathematics
2 answers:
kykrilka [37]2 years ago
4 0

Answer:

B. 3

Step-by-step explanation:

we know 2x3 = 6 soo just add 2 zeros = 600

sasho [114]2 years ago
4 0
B) 3 if we multiply 200 by 3 the answer will be 600
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What is the greatest 0.45 0.097 0.375 0.209
Nady [450]

Answer:

Largest number is : 0.45

Step-by-step explanation:

0.45, 0.097, 0.375, 0.209

Here all numbers have first digit is 0.

So, look at the first decimal place from all decimal numbers.

4 from .45, 0 from .097, 3 from .375 and 2 from .209

Largest digit is 4

So, largest digit is 0.45

So, final answer is 0.45

I hope it will help you.

If you have any doubt, please leave a comment. I'll help you.

3 0
3 years ago
Read 2 more answers
I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an
Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

\mu = 0 - 5 = -5

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - (-5)}{\sqrt{13}}

Z = \frac{6}{\sqrt{13}}

Z = 1.66

Z = 1.66 has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0
3 years ago
Simplify each of the following:<br> 2<br> 1. (3+4i ) + ( 19 - 5i)
ira [324]

I hope this helps you

(3+19)+(4i-5i)

22-i

6 0
3 years ago
PLEASE HELP! GIVING POINTS! PLEASE EXPLAIN IF YOU CAN :)!
jolli1 [7]

Answer:

if I am correct 2/3 is bigger than 0.65

and I think 5.5 is smaller than 5 3/7

and I think the order goes 3/8 5/6 1/2

8 0
3 years ago
Whats the answer i need help
julia-pushkina [17]
Answer)3.5
1)minus 17.5-14=3.5
2)14+3.5=17.5
3)keep adding 3.5
6 0
3 years ago
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