So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.
Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4
So then we get 8x^4/(x^(3/4)+7x)^4
8x^4/(x^(3/4)+7x)^4
Answer:
The initial value is 2
Step-by-step explanation:
Answer:
the answer is -5
Step-by-step explanation:
There are four 6's and four 9's.
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