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Anit [1.1K]
3 years ago
9

Mt. Young bought some hamburgers for his cookout. The price was $32,17, but, le found that hamburger parties were on special for

$22.692. What was hubs DOcent Bio
A $3.20
B. 29.68%
OC45%
D. $87.25
Mathematics
1 answer:
Anna35 [415]3 years ago
3 0
B- 29.68%
A is too little
C is too much off
D is way too much
So B is your answer
You might be interested in
ULT ma<br> 4. Write an expression, then evaluate.<br> a. 1/4of the sum of 18 and 6
OlgaM077 [116]

Answer: Required expression: \dfrac14\times(18+16)

Result: \dfrac{17}{2}

Step-by-step explanation:

Given phrase:  " \dfrac14\text{ of the sum of } 18\text{ and }6. "

Required expression: \dfrac14\times(18+16)    ['+' used to express sum, 'x' used in place of 'of']

Since 18+16 = 34

Then,

\dfrac14\times(18+16)=\dfrac14\times34  \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}

Hence,     \dfrac14\times(18+16)=\dfrac{17}{2}.  

8 0
3 years ago
Cylinder A has radius r, height h, and a volume of 10pi cubic units. Cylinder B has twice the radius and twice the height.
viva [34]

Answer:

Step-by-step explanation:

10 = r²h

(2r)²(2h) = 16r²h

volume of B is 1.6 times the volume of A

4 0
3 years ago
Read 2 more answers
A study shows that employees who begin their workday at 9:00 a.m. vary their times of arrival uniformly from 8:40 a.m. to 9:30 a
jeka94

Answer:

0.2 or 20%

Step-by-step explanation:

If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.

The range between 8:40 and 9:30 is 50 minutes.

The range between 9:00 and 9:10 is 10 minutes.

Therefore, the  probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:

P(9:00\leq X\leq 9:10)=\frac{10}{50}=0.20=20\%

The probability is 0.2 or 20%.

6 0
3 years ago
Given z1 = -3
trasher [3.6K]

Answer:

See explanation

Step-by-step explanation:

The given complex number are:

z_1=-3\sqrt{3}+3i

and

z_2=6\cos 150\degree+6i\sin 150\degree

When we rewrite z_1=-3\sqrt{3}+3i in complex form, we obtain;

z_1=r(\cos \theta+i\sin \theta)

where

r=\sqrt{(-3\sqrt{3})^2+3^2 }=\sqrt{36}=6

and

\theta=tan^{-1}(\frac{y}{x})

\implies \theta=tan^{-1}(\frac{-3\sqrt{3}}{3})=150\degree

Hence,

z_1=6(\cos 150\degree+i\sin 150\degree)

z_1=6\cos 150\degree+6i\sin 150\degree

Hence

z_1=z_2

8 0
3 years ago
No link need right answer
serious [3.7K]

Answer:

1/9 of the cube

Step-by-step explanation:

5 0
3 years ago
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