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2 years ago

Arrange these numbers from least to greatest:

Mathematics

1 answer:

Sindrei [870]2 years ago

8 0

-3/7 is obviously the least because it is a negative number.Then 2/5 because if you think about it if 2/5 is 2 of 5 equal pieces. 2/3 is 2 of 3 pieces.So if you think about a pizza if you cut the pizza into 3 pieces and ate 2 imagine how much you would have left and then think about cutting the pizza into 5 pieces and only eating 2 . Think about that. So the answer in the end is -3/7,2/5, and then 2/3. Hope I helped!

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Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

Find the range of the data. scores: 84, 83, 80, 95, 99, 95, 83, 83, 92, 84

In-s [12.5K]

To find the range of these scores, we must take the largest scores and subtract the smallest from it.

The largest score is 99, and the smallest score is 80.

99 - 80 = 19

3 0

3 years ago

Read 2 more answers

Which of the expressions below have exactly 3 terms? Select all that apply.

Fynjy0 [20]

Answer:

C. 6x + 9 - 3x^2

Step-by-step explanation:

We have 4 expressions and are being asked which has 3 terms.

When it comes to terms, terms are numbers that are different, it could be separated through a variable, square root, symbol, e.t.c.

So when looking for an answer, we need 3 numbers with different variables or symbols, let's look

A. only has two, 10x and 8. Therefore it is wrong.

B. has 4 terms, 3x^3, 6x^2, 9x, and 12. Therefore it is wrong.

C. is correct because it has 3 terms, 6x, 9, and 3x^2.

D. has 2 terms, 833 and 12x, though 16 is there, it is the same as 833, therefore not counting it as its own term.

7 0

2 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2