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3 years ago

Solve the equation . The solution of the equation is .

Mathematics

2 answers:

Andrews [41]3 years ago

6 0

Answer:how were going to solve the equation and the equation is not there

Step-by-step explanation:

KonstantinChe [14]3 years ago

3 0

The answer is Undefined

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(sinA-cosA+1)/(sinA+cosA-1)=2(1+cosecA)

borishaifa [10]

Answer:

The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

Step-by-step explanation:

Given Trigonometrical function as :

$\frac{sin A - cos A + 1}{sin A + cos A - 1}$ = 2 (1 + cosec A)

Or, $\frac{sin A + ( 1 - cos A)}{sin A - (1 - cos A)}$ = 2 (1 + cosec A)

, Now, rationalizing

$\frac{(sin A + ( 1 - cos A)) \times (sin A + (1 - cosA))}{(sin A - (1 - cos A))\times (sin A + (1 - cos A))}$ = 2 (1 + cosec A)

Or, $\frac{(sin A + (1 - cos A))^{2}}{sin^{2} - (1-cos A)^{2}}$ = 2 ( 1 + $\dfrac{1}{\textrm sinA}$

Or, $\frac{sin^{2}A + (1 - cosA)^{2} + 2 \times sin A \times (1 - cos A)}{sin^{2}A - (1 + cos^{2}A - 2 cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - 1 - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{sin^{2}A + 1 + cos^{2}A - 2 cos A + 2 sin A - 2 sin A cos A}{sin^{2}A - (sin^{2}A + cos^{2}A) - cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{2- 2 cos A + 2 sin A - 2 sin A cos A}{- 2cos^{2}A +2 cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{1- cos A + sin A - sin A cos A}{- cos^{2}A + cos A}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) + sin A (1-cos A)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1- cos A) (1 + sinA)}{cos A(1 - cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, $\frac{(1 + sinA)}{(cos A)}$ = 2 ( $\dfrac{1 + sin A}{sin A}$

Or, sin A + sin² A = 2 cos A (1 + sin A)

Or, sin A + sin² A = 2 cos A + 2 cos A × sin A

Or, sin² A + sin A - 2 cos A - 2 cos A × sin A = 0

So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0 Answer

6 0

3 years ago

Find a solution to the following system of equations. −2x + y = −3 −x + 2y = 3

exis [7]

Multiply the first equation by -2 to give

4x - 2y = 6
-x + 2y = 3 Adding:-
3x = 9
x = 3
Plug x = 3 into second equation:-
-3 + 2y = 3
2y = 6
y = 3

Answer is x=3, y = 3

5 0

3 years ago

Read 2 more answers

Solve the equation below 9 = x/18 x= What is X?

dedylja [7]

X=162, if you multiply 18*9 which is the way to get the answer you get 162

7 0

3 years ago

PLEASE HELP!!! Hshehebsjahsvsvabsbbsbs

IRISSAK [1]

Answer:

i think its like 9.14 or sumthin

Step-by-step explanation:

is tht NWEA? lol

5 0

3 years ago

Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the cho

Gnom [1K]

Answer:

Rasheed bought 3 packages of chocolate and 5 packages of toffee.

Step-by-step explanation:

In this case we have to found the number of bars that multiplied by the fractions presented give us an integer number and meets with the fact that the bars are an odd number because the packages came in packs of two bars.

For the case of the chocolate we have to find a number that meets this characteristics, we try with the number 6:

$6*\frac{2}{3} =4$

For chocolate Rasheed bought 3 packages, we can see that 6 bars meet the asked.

For the case of toffee, we try with number 10:

$10*\frac{3}{5} =6$

For toffee Rasheed bought 5 packages, we can see that 10 bars meet the asked.

Rasheed bought 3 packages of chocolate and 5 packages of toffee.

5 0

3 years ago