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Sveta_85 [38]
3 years ago
10

Evaluate the quotient of 1.05 x 103 and 1 x 103

Mathematics
1 answer:
agasfer [191]3 years ago
8 0

Answer:

for the 1st one it is 108.15x

and the 2nd it is 103x

Step-by-step explanation:

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algol [13]
24 times 10 with the exponent as 4
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7% of 120 (Need work shown)
inessss [21]
1% of 120 is 1.2, so 7 *1.2 = 8.4

Also you could set up the proportion 7/100 = x/120 and solve for x.
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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
4 years ago
Please help me solve this.
Vlada [557]

Answer:

<h2>I think that is a FORMULA.</h2>

it can't be solved if we don't know the values of atleast one of the x and y.

Hope this helps.

Good luck ✅.

8 0
2 years ago
Find the volume of the solid. 4km, 8km, and 12km
ahrayia [7]
Bussneshxhdbdbdbdbdhddhxhhdhdhdhdhdhdbdbdbddbbdndbdbdbdbdbdbd
8 0
3 years ago
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