Answer:
below
Step-by-step explanation:
that is the procedure above
Are you learning how to arc things
Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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The probability that it is British is 0.6164 if the Venn diagram shows the information about a stamp collection. f = 100 stamps in the collection A = stamps in the 20th century B = British stamps A B. X(X - 6) х 2x + 32 28 A stamp is chosen at random.
<h3>What is the Venn diagram?</h3>
It is defined as the diagram that shows a logical relation between sets.
The Venn diagram consists of circles to show the logical relation.
We have:
f = 100 stamps in the collection
A = stamps in the 20th century
B = British stamps
We can make a linear equation to solve for x as the total stamps are 100 in the collection.

After solving x = 9.88, or x = -6.88
Probability can't be negative so neglecting the negative ones
x = 9.88
The probability that it is British:

= 61.64/100
= 0.6164
Thus, the probability that it is British is 0.6164 if the Venn diagram shows the information about a stamp collection. f = 100 stamps in the collection A = stamps in the 20th century B = British stamps A B. X(X - 6) х 2x + 32 28 A stamp is chosen at random.
Learn more about the Venn diagram here:
brainly.com/question/1024798
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