1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
g100num [7]
3 years ago
14

a graph show the relationship between an employee total earnings,in dollars ,and the number of hours the employee works.

Mathematics
1 answer:
True [87]3 years ago
5 0
What is the question?
You might be interested in
(Will give Brainliest/5 Stars if correct answer)
tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

7 0
3 years ago
The locations, given in polar coordinates, for two planes approaching an airport are (4 mi, 12º) and (3 mi, 73º). Find the dista
finlep [7]
Distance formula = sqrt[(4^2 + 3^2) - 2(3×4)cos(73-12)]

sqrt[(25) - 24cos(61)]

sqrt(25 - 11.64)

sqrt(13.36)

final answer = 3.66

Hope this helps!
5 0
3 years ago
Read 2 more answers
Recent homebuyers from a local developer allege that 30% of the houses this developer constructs have some major defect that wil
umka21 [38]

Answer:

3.54% probability of observing at most two defective homes out of a random sample of 20

Step-by-step explanation:

For each house that this developer constructs, there are only two possible outcomes. Either there are some major defect that will require substantial repairs, or there is not. The probability of a house having some major defect that will require substantial repairs is independent of other houses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

30% of the houses this developer constructs have some major defect that will require substantial repairs.

This means that p = 0.3

If the allegation is correct, what is the probability of observing at most two defective homes out of a random sample of 20

This is P(X \leq 2) when n = 20. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.3)^{0}.(0.7)^{20} = 0.0008

P(X = 1) = C_{20,1}.(0.3)^{1}.(0.7)^{19} = 0.0068

P(X = 2) = C_{20,2}.(0.3)^{2}.(0.7)^{18} = 0.0278

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0008 + 0.0068 + 0.0278 = 0.0354

3.54% probability of observing at most two defective homes out of a random sample of 20

5 0
3 years ago
Not sure need help please​
Varvara68 [4.7K]

Answer:

Explanation and problem 1 solved below.

Step-by-step explanation:

The quadrants are numbered this way:

Quadrant 1: upper right

Quadrant 2: upper left

Quadrant 3: lower left

Quadrant 4: lower right

Signs of coordinates in the quadrants:

x-coordinate is positive in Q1 and Q4

x-coordinate is negative in Q2 and Q3

y-coordinate is positive in Q1 and Q2

y-coordinate is negative in Q3 and Q4

1. (-1, 5)

x is negative, so it is Q2 or Q3

y is positive, so it is Q1 or Q2

The quadrant in common is Quadrant 2

Answer: quadrant 2

4 0
3 years ago
Solve the system of equations. y = x − 5 and y = x2 − 5x + 3 A. (-4,-9) and (-2,-7) B. (4,-9) and (2,-7) C. (4,-3) and (2,-1) D.
larisa [96]

Answer:

D

Step-by-step explanation:

Given the 2 equations

y = x - 5 → (1)

y = x² - 5x + 3 → (2)

Substitute y = x² - 5x + 3 into (1)

x² - 5x + 3 = x - 5 ← subtract x - 5 from both sides

x² - 6x + 8 = 0 ← in standard form

(x - 2)(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 4 = 0 ⇒ x = 4

Substitute each of these values into (1) for corresponding values of y

x = 2 → y = 2 - 5 = - 3 ⇒ (2, - 3 )

x = 4 → y = 4 - 5 = - 1 ⇒ (4, - 1 )

4 0
4 years ago
Read 2 more answers
Other questions:
  • Please help.. what is the function rule for the perimeter P of a building with a rectangular base if the width w is two times th
    14·2 answers
  • 5 + h &gt;7 what is the answer to this math problems
    9·1 answer
  • The sum of six consecutive integers is 675. What is the FIRST of the four integers?
    15·1 answer
  • What is the slope of the line?<br> N/
    8·1 answer
  • The question is down below
    7·1 answer
  • a picture 10 1/4 feet long is to be centered on a wall that is 14 1/2 feet long. How much more space is there from the edge of t
    6·1 answer
  • Find three consecutive even integers such that the sum of the least integer and the middle integer is 22 more than the greatest
    7·1 answer
  • A triangle has side lengths of 24 cm, 24 cm, and 24 cm.
    6·2 answers
  • Of the 81 teenagers at youth camp, 73% have a
    7·1 answer
  • Help
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!