draw hundred boxes, ten sticks, and circles to show a number between 100 and 200. what number did you show?

A bag contains 5 red cubes and 7 white cubes. Celinda will select one cube, put it in her pocket, and then select a second cube.

GenaCL600 [577]

Answer:

The expression which gives the probability that she will select two red cubes = 5/12 * 4/11 ....

Step-by-step explanation:

According to the statement there are 4 red cubes and 7 white cubes.

The total number of cubes are = 7+5 = 12

If she picks up one red cube then the number of ways of picking up red cubes out of 12 is = 5/12

If she picks up 2nd red cube then the number of ways of picking up 2nd red cube = 4/11

Therefore the expression which gives the probability that she will select two red cubes = 5/12 * 4/11 ....

4 0

3 years ago

During the summer of 2014, Coldstream Country Club in Cincinnati, Ohio collected data on 443 rounds of golf played from its whit

lys-0071 [83]

Answer:

Step-by-step explanation:

Hello!

You have the data on 443 rounds of golf played on the 12th hole.

The variable of interest is:

X: score of one round of golf played on the 12th hole.

To construct the empirical distribution of the discrete variable you have to organize the data from least to highest and count how many times each score was recorded, establishing the absolute frequency for each value of the variable.

a. Check attachment.

fi= absolute frequency

Fi= accumulated absolute frequencies

hi= relative frequency

Hi= accumulated relative frequency

b.

P(X≤4)

This is the probability of the player scoring "4 or less", so it includes the probability of the player scoring 3 and the player scoring 4, symbolically:

P(X≤4)= P(X=3)+P(X=4)= H(4)= 0.136

c.

The expected score of a discrete variable is:

E(X)= [∑(Xi*fi)]/n= 2343/443= 5.29

d.

To calculate the variance of the variable you have to use the following formula:

V(X)= 1/(n-1)*[∑(Xi²*fi)-(∑(Xi*fi)²]/n)] = (1/442)*[12831-(2343²/443)]

V(X)= 0.993

e.

The standard deviation is the square root of the variance:

√V(X)=√0.993= 0.994

I hope it helps!