The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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Answer:
The answer is 10x^6 * sqrt x
Step-by-step explanation:
Hope it works
Answer:
40 minutes
Step-by-step explanation:
12 envelopes every 10 minutes.
48 envelopes = 40 minutes
Answer:
3.16 units
Step-by-step explanation:
It has been given that the triangles JKL and the triangle RST are congruent.
That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.
Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are 
and 
.
The length of the side RS is equal to the distance between point R and S.
RS 
Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.
Answer:
because x is the middle integer of three consecutive integers
=> The remaining 2 numbers respectively are x - 1 and x + 1
=> the sum of these three integers is
x - 1 + x + x + 1 = 3x
