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astraxan [27]
3 years ago
12

Waldnice!

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

Answer:

The maximum and minimum temperatures recorded by the thermometer when checked by Wednesday morning are 5°C and -5°C

Step-by-step explanation:

The given parameters are;

A maximum and minimum thermometer is used which records maximum and minimum values as follows;

Initial temperature on Sunday at the time of resetting the thermometer = 4°C

Temperature drop overnight = 5°C, new low = 4 - 5 =  -1°C,

Temperature rise on Monday = 6°C. New high = -1 + 6 = 5°C

Temperature drop on Monday night = 10°C. New low = 5 - 10 = -5°C

Temperature rise on Tuesday = 4°C = New high = 4 + - 5 = -1°C

Temperature drop on Tuesday night = 2°C. New low = -1 - 2 = -3°C

Therefore, the maximum and minimum temperatures recorded by the thermometer when checked by Wednesday morning are 5°C and -5°C.

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Free pointsss whats 90 plus 3 divided by the amount of fingers you have
Gekata [30.6K]

Answer:

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Step-by-step explanation:

90+3 = 93

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7 0
3 years ago
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Tcecarenko [31]
The answer to this would be 6
8 0
3 years ago
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Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0
3 years ago
Ravi ordered some books online and spent a total of $89. Each book cost $5 and he paid a total of $4 for shipping. How many book
Katyanochek1 [597]

Answer:

He bought 17 books.

Step-by-step explanation:

Given that:

Total money spent = $89

Cost of each book = $5

Shipping price = $4

We have to find, Total number of books

So if the number of books be represented by b, the equation will become:

Cost of one book * total number of books + shipping price = total money

Putting values we get:

5*b + 4 = $89

By simplifying:

5*b = 89 - 4

5*b = 85

Dividing both sides by 5 we get:

b = 17

So the total number of books bought is 17.

i hope it will help you!

7 0
3 years ago
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