Answer:
x = -1, y = 2 and z = 1
Step-by-step explanation:
The given system of equations are :
2x - y + 3z= -1 ....(1)
x + 2y - 4z = -1 ......(2)
y – 2z = 0 .....(3)
Equation (3) can be written as :
y = 2z
Use y = 2z in equation (2)
x + 2(2z) - 4z = -1
x + 4z - 4z = -1
x = -1
Put the value of x in equation (1) :
-2 -y +3z = -1
-y+3z = 1 ....(4)
Adding equation (3) and (4)
y-2z+(-y+3z)=1
z = 1
Now put z = 1 in equation (4)
-y+3=1
-y = -2
y = 2
Hence, the values of x,y and z are -1, 2 and 1 respectively.
Divide top and bottom by any number that's fits into both of them keep doing that until it's not possible Hope that helped Have a good day! :-)
Answer:
109 is the correct answer
If you would like to solve the equation 2 * x^2 + 8 * x = x^2 - 16, you can calculate this using the following steps:
<span>2 * x^2 + 8 * x = x^2 - 16
</span><span>2 * x^2 - x^2 + 8 * x + 16 = 0
</span>x^2 + 8 * x + 16 = 0
(x + 4) * (x + 4) = 0
x = - 4
<span>The correct result would be x = - 4.</span>
