Question

Find the preimage of the point (4, 3) under the given transformation. A transformation T : (x, y) (x - 2, y + 3) (2, 6) (2, 3) (6, 3) (6, 0)

Answer 1

Answer:

The preimage is $(6,0)$

Step-by-step explanation:

The given point is (4,3).

The translation rule is

$T:(x,y)\rightarrow (x-2,y+3)$

Let $(a,b)$ be the preimage.

Then,

We apply this rule to the preimage to obtain;

$T:(a,b)\rightarrow (a-2,b+3)$

This implies that;

$a-2=4$

$\Rightarrow a=4+2$

$\Rightarrow a=6$

Also,

$b+3=3$

$\Rightarrow b=3-3$

$\Rightarrow b=0$

Hence the preimage is $(6,0)$