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expeople1 [14]
3 years ago
13

How to solve for the missing side useing the pythagorean theorem

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

<em>cos</em><em> </em><em>=</em><em> </em>

<em>\frac{adjacent}{hypotsus}</em>

<em>coß</em><em> </em><em>=</em><em> </em><em>9</em><em>÷</em><em>15</em>

<em>the</em><em> </em><em>missing</em><em> </em><em> </em><em>side</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>6</em><em> </em><em>nor</em><em> </em><em>3</em><em>/</em><em>5</em>

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Help with math please!
My name is Ann [436]

Answer: 8^10

Add up the exponents 6 and 4 to get 6+4 = 10. This is using the rule a^b*a^c = a^(b+c). In this case, a = 8, b = 6, c = 4.

7 0
3 years ago
Read 2 more answers
Find the perimeter of a rectangle whose length is 3 cm greater than its height, and whose area is 40 cm².
jonny [76]

Answer: 26\ cm

Step-by-step explanation:

The perimeter of a rectangle can be calcualated with this formula:

P=2l+2h

Where "l" is the lenght and "h" is the height.

 The area of a rectangle can be found with this formula:

A=lh

Where "l" is the lenght and "h" is the height.

In this case we know that:

A=40\ cm^2

Therfore, we can susbsitute them into A=lh and solve for "h" in  order to find its value:

40=(h+3)h\\\\40=h^2+3h\\\\h^2+3h-40=0

Find two number whose sum is 3 and whose product is -40. These are -5 and 8. Then, factorizing, we get:

(h-5)(h+8)=0\\\\h_1=5\\\\h_2=-8

The positive value is the height. Then:

h=5\ cm

Since the length is 3 centimeters greater than its height, we get that this is: Then:

l=5\ cm+3\ cm\\\\l=8\ cm

Substituting values into P=2l+2h, we get that the perimeter is:

P=2(8\ cm)+2(5\ cm)\\\\P=26\ cm

8 0
3 years ago
Read 2 more answers
Im having trouble on this
Degger [83]

Answer: girl no

Step-by-step explanation:

3 0
3 years ago
Hello, who would you do me the favor of helping me with this question?
Fed [463]

Step-by-step explanation:

diagonal of a polygon formular =sum of diagonal =5-3-5/2. A triangle do not have diagonal

4 0
3 years ago
Tangent please help me
atroni [7]
A^2+ b^2= c^2
24^2+b^2=25^2
576+b^2=625
Sub 576
b^2= 49 b=7
6 0
3 years ago
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