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tensa zangetsu [6.8K]
3 years ago
5

Geometry help!!

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0
It would be A, Side Angle Side (SAS).  Because you are given we congruent sides, and tow right angles.  Using the reasoning of "If two two angles are both right angles then they are congruent" you can prove the angles congruent. 

The reason it is not HL is because HL is used when it is given a right angle and the hypotenuse and one of the legs congruent.  Therefore the only choice is Side Angle Side (SAS).
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Symposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable
notsponge [240]

Complete Question

ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.  

a. What is the value of the sample test statistic? (Round your answer to two decimal places.)  

b. Find the P-value of the test statistic. (Round your answer to four decimal places.)

Answer:

a) Z=2.45

b) P Value=0.0073

Step-by-step explanation:

From the question we are told that:

Probability of Wishart and Leach P=21.4=>0.214

Population Size N=498

Sample size n=12

Therefore

P'=\frac{129}{498}

P'=0.2590

Generally the Null and Alternative Hypothesis is mathematically given by

H_0:P=0.214

H_a:=P>0.214

Test Statistics

Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}

Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}

Z=2.45

Therefore P Value is given as

P Value =P(Z\geq 2.45)

P Value =1-P(Z\leq 2.45)

P Value =1-0.99268525

P Value=0.0073

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2 years ago
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Answer:

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Part C) tan(A)=\frac{2\sqrt{42}}{19}

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

sin(A)=\frac{BC}{AB}

substitute the values

sin(A)=\frac{2\sqrt{42}}{23}

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

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cos(A)=\frac{AC}{AB}

substitute the values

cos(A)=\frac{19}{23}

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

tan(A)=\frac{BC}{AC}

substitute the values

tan(A)=\frac{2\sqrt{42}}{19}

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Answer:

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Step-by-step explanation:

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Answer:

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