Question

IM SO LOST PLEASE HELP

Answer 1

Check the picture below.

$\bf \textit{lateral area of a cone}\\\\ LA=\pi r\stackrel{slant-height}{\sqrt{r^2+h^2}}~~ \begin{cases} LA=539\pi \\ r=49 \end{cases}\implies 539\pi =\pi 49\sqrt{r^2+h^2} \\\\\\ \cfrac{539\pi }{49\pi }=\sqrt{r^2+h^2}\implies 11=\sqrt{r^2+h^2}$