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podryga [215]
4 years ago
15

Help Please

Mathematics
2 answers:
KonstantinChe [14]4 years ago
6 0
22 phone call because 34+42=76 so 76+22=98


Nostrana [21]4 years ago
5 0

1st month= 34

2nd month=42

add them together to get= 76

then do 98-76= 22

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Simplify the expression: <br> 10x–8xy–3xy<br><br> 2ab–7ab+7a2<br><br> –a^4+2a^3–4a^4+2a^2–3a^2
Mila [183]
10x - 8xy - 3xy
= x ( 10x - 11xy )
8 0
4 years ago
What is volume and how is it measured?<br>​
Lelu [443]

Answer: Volume is the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains. ... Volume is often quantified numerically using the SI derived unit, the cubic metre.

Step-by-step explanation:

SI unit: Cubic metre

Other units: Litre, fluid ounce, gallon, quart, pint, ...

In SI base units: 1 m3

Dimension: L3

4 0
3 years ago
Simplify 659/8 . What is the answer rounded to the nearest whole number? 82 83 84
fredd [130]
659 divided by 8 = 82 R3.

So the answer is 82.
4 0
4 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
Which ordered pair is a solution of the equation? y=8x+3y=8x+3
Mrac [35]

Multiply the first equation by 4 (so that both equations will have 8x terms) and then subtract:  

8x-20y = -24

8x +3y = 68

------------

0 -23y = -92  

Now divide both sides by -23:  

y = 4  

Find x by plugging y=4 into either equation:  

8x +3(4) = 68

8x = 68 - 12

8x = 56

x = 7  

So the answer is ordered pair is (7,4)

3 0
3 years ago
Read 2 more answers
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