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3 years ago

Hhhhhheelllp ASAPpppppp

Mathematics

2 answers:

Anastaziya [24]3 years ago

6 0

Answer:

Step-by-step explanation:

Alex787 [66]3 years ago

5 0

Minus both of the numbers

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Using coupons you spell $91 grocery shopping this is 65% of the total retail price of groceries how much would you have spent if

Andrews [41]

$140 because

$91 divided by 65 is 1.4
1.4 times 100 is 140

3 0

3 years ago

4a. If (11+x) is positive, but (4+x) is negative, what is one number that x could be?

sattari [20]

Answer:

Step-by-step explanation:

x has to be equal to or less than a -5 to get (4 + x) to be a negative number.

x has to be equal to or greater than -10 for (11 + x) to be a positive number.

Therefore, any number between -10 and -5 will work.

8 0

3 years ago

What is the inverse one to one function of f(x) = square root of x-2???

alexira [117]

$f(x) = \sqrt{x - 2} \\y = \sqrt{x - 2} \\y^{2} = (\sqrt{x - 2})^{2} \\y^{2} = x - 2 \\x^{2} = y - 2 \\x^{2} + 2 = y \\x^{2} + 2 = f^{-1}(x)$

6 0

3 years ago

A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w

AfilCa [17]

Answer:

$\frac{15}{4802}$ , $\frac{15}{9604}$ , $\frac{9}{2401}$ , $\frac{9}{4802}$

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: $\frac{4}{14}$

green: $\frac{2}{14}$

yellow: $\frac{3}{14}$

blue: $\frac{5}{14}$

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = $\frac{3}{14} \cdot \frac{4}{14} \cdot \frac{2}{14} \cdot \frac{5}{14} =\frac{15}{4802}$

Removing 1 blue, 1 green, 1 green, and 1 yellow = $\frac{5}{14} \cdot \frac{2}{14} \cdot \frac{2}{14} \cdot \frac{3}{14} =\frac{15}{9604}$

Removing 1 red, 1 red, 1 yellow, and 1 yellow = $\frac{4}{14} \cdot \frac{4}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} =\frac{9}{2401}$

Removing 1 green, 1 yellow, 1 yellow, and 1 red = $\frac{2}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} \cdot \frac{4}{14} =\frac{9}{4802}$

4 0

2 years ago

A movie theater is holding a contest for people who are in line before 10 p.m. The people who are within three places of the 99

pav-90 [236]

Answer:

|x-99|<3

Step-by-step explanation:

|x-99|<3

4 0

4 years ago