Answer: (C) {x | x R, x > 3}
Explanation:
Solve the inequality for x:
x -5 > -2 | add 5
x > -2 + 5
x > 3
Solution set: all Reals x > 3, or {x | x R, x > 3}
X2+12x+11=0
x2+12x+(12/2)^2-(12/2)^2+11=0
(x+6)^2-36+11=0
(x+6)^2=25
(x+6)=+-5
x= +5-6 or -5-6
= -1 or- 11