Answer:
Explanation:
Environmental changes occurs from time to time, we have the short term changes that do not last for a very long time and the long term changes that last for a while. Accumulate of short term changes can extend to long term as some of the long term effects are as a results of short term changes in the environment.
Short term environment changes can be favourable to some organism and adversely affect others. Raining season causes increase in growth and development of most plant species but a long period of drought and dryness makes its hard for some plant to strive while some plants can strive well in long period of drought. This makes the two changes different, the both have individual effects on plants response.
Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. This process is required to produce egg and sperm cells for sexual reproduction. During reproduction, when the sperm and egg unit to form single cell for sexual reproduction. During reproduction, when the sperm and egg unit to form a single cell, the number of chromosome is restored in the offspring.
Meiosis begins with a parent cell that is diploid, meaning it has two copies of each chromosome. The parent cell undergoes one round of DNA replication followed by two separate cycles of nuclear division. The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
The male produces the what ever it’s called
<span>I think the answer woulb be option B). S</span><span>olenoid wrapped around an iron core, wires, a light bulb</span>
