Factor:
2sin^2x-sinx = 0
sinx(2sinx - 1) = 0
Therefore the solutions are when:
sin x = 0
And
sinx = 1/2
So sinx = 0
is true when x = 0 and pi and all the angles coterminal with these points. Thus, the answer is x = pi*n, (where n is some integer)
sinx = 1/2
is true when x = pi/6 and 5pi/6 and the angles coterminal with these points.
Thus, the answer is x = pi/6 + 2pi*n (where n is some integer)
and x = 5pi/6 + 2pi*n (where n is some integer)
Answer:
B'C' = 2
Step-by-step explanation:
Just took the FLVS test and it was correct
4a+8=14-6+4a. 4a+8=8+4a so I think it's B
847 over 100 that is the answer
6 + 12 = 18
18 + 24 = 42
Double the difference between every 2 numbers (12 x 2 = 24 x 2 = 8)
42 + 48 = 90
90 is the missing number
Happy to Help!