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creativ13 [48]
3 years ago
7

How do I solve -3x = 9

Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

Step-by-step explanation:

-3 times a number (positive) till you get 9

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otez555 [7]

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8 0
3 years ago
Complete the square than convert to vertex form. y=2x^2+8x-9​
8_murik_8 [283]

y=2x^2+8x-9\\D=b^2-4ac\\D=64-4(2)(-9)\\D=64+72 > 0

There are 2 roots so the only way to complete the square is,

y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17

Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.

then complete the square and multiply 2 inside the brackets.

subtraction as you already get the vertex form and know how to complete the square.

Vertex Form: y=2(x+2)^2-17

3 0
3 years ago
3(12-3y^2) Help solve this please
HACTEHA [7]
Step 1. <span>Distribute

</span>3*12+3*-3 y^{2}
<span>
Step 2. Simplify </span>3*12 to 36

36+3*-3 y^{2}

Step 3. Simplify 3*-3 y^{2} to -9 y^{2}

36-9 y^{2}

Done! :)
5 0
3 years ago
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