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2 years ago

What is the value of each variable?

Mathematics

1 answer:

Bond [772]2 years ago

3 0

Answer:

∠a = 1/2(95) = 47.5°

∠b = 90°

arc = (180 - 47.5 - 90)(2) = (42.5)(2) = 85°

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Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago

The average national utility price is $270.48. Over a 6-month period, what is the average utility price in Orlando? How does thi

Svetllana [295]

Answer:

Step-by-step explanation:

6 0

3 years ago

URGENT PLS HELP MAX POINTS

bija089 [108]

Answer:

-103

243

Step-by-step explanation:

(q•r)(5) = q(r(5))

r(5) = 2(5²) + 1 = 51

q(51) = -2(51) - 1 = -103

(r•q)(5) = r(q(5))

q(5) = -2(5) - 1 = -11

r(-11) = 2(-11)² + 1 = 243

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3 years ago

Ax+by+c=0 solve for y

kvv77 [185]

$Answer: \large\boxed{y=\frac{-ax}{b} -\frac{c}{b}}$

Step-by-step explanation:

$ax+by+c=0\\ax+by=-c\\by=-ax-c\\y=\frac{-ax-c}{b}\\y=\frac{-ax}{b} -\frac{c}{b}$

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2 years ago

Solve the equation : 2x + 7 = 21 and find the value of x. Is 2x + 7 = 21 a first degree equation or not?

Paraphin [41]

Answer:

The proposed equation is solved as follows:

2X + 7 = 21

2X = 21 - 7

2X = 14

X = 14 / 2

X = 7

The value of X is 7.

A first degree equation is an algebraic equation in which each term is either a constant or a product of a fixed term on a single variable. Therefore, this equation is a first degree one, since it only has a single variable, which is X.

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2 years ago