Answer:
U have selected the correct answer..... Option 3rd is the correct
Answer:
Step-by-step explanation:
Rectangle A measures 8 inches by 4 inches. Rectangle B is a scaled copy of Rectangle A. Select all of the measurement pairs that could be the dimensions of Rectangle B.
15 inches by 11 inches
6 inches by 3 inches
18
6 inches by 2 inches
12
16 inches by 8 inches
10 inches by 5 inches
15 inches by 7.5 inches
10 inches by 6 inches
The main rules that we use here are :
i)

for nonnegative values a and b.
ii)

.
Thus, first 'decompose' the numbers in the radicals into prime factors:

.
By rule (i) we write:

.
We can collect these terms as follows:

, and by rule (ii) we have:

Answer:

.
The answer is 4.51.............