Answer:
The z-statistic for this test is -1.547 and P-value of the test is 0.0618
Step-by-step explanation:
An article in the Washington Post on March 16, 1993 stated that nearly 45 percent of all Americans have brown eyes.
We are given that A random sample of n=82 C of I students found 30 with brown eyes.
n = 82
x = 30
Now to find z statistic we will use one sample proportion test
Formula of test statistic =
=
=
So, the z-statistic for this test is -1.547
Now refer the z table for p value .
p value = 0.0618
The P-value of the test is 0.0618
Hence the z-statistic for this test is -1.547 and P-value of the test is 0.0618