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4 years ago

Find the area of this shape shown below

Mathematics

2 answers:

il63 [147K]4 years ago

6 0

Answer: 8

Step-by-step explanation:

KiRa [710]4 years ago

5 0

Answer:

The answer is 8units^2.

#Hope it helps uh......

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Find the value of the following expression: (2^8 • 5^-5 • 19^0)^-2 • (5^-2 over 2^3)^4 • 2^28. Write your answer in simplified f

DaniilM [7]

Recognize that "( ) over 2^3" means ( ) • 2^-3. Use the rule of exponents
.. (a^b)^c = a^(b•c)

= 2^-16•5^10•19^-2 • 5^-8*2^-12 • 2^28

Now, you can use the rule of exponents
.. (a^b)*(a^c) = a^(b+c)

= 2^(-16 -12 +28) • 5^(10 -8) • 19^-2
= 5^2 • 19^-2
= 5^2 / 19^2
= 25/361

3 0

4 years ago

Is 50 a perfect square ? Explain your answer please

xeze [42]

No, 50 is not a perfect square. A perfect square is any number that can be divided by any number to get the quotient as the same number AND the quotient must be rational. When you divide 50 so that the quotient equals the divisor, you will get an irrational number. Therefore, 50 is not a perfect square.

3 0

4 years ago

Read 2 more answers

Is the value of the 2 in 23,406 ten times as great as the value of 3 ?

Kisachek [45]

Answer:

Step-by-step explanation:

Short answer yes if the intent of the question is talking about place values.

2 is in the thousands position

3 is in the hundreds position.

So if that's the question, the answer is yes.

6 0

3 years ago

Prove segment GF = segment HF

Llana [10]

Answer:

GF = FH

Step-by-step explanation:

GEF & FIH

EF = FI (equal)

GEF = FIH (alternate angle)

EG = HI (parallel sides equal)

GEF & FIH are congruent, under the case of (SAS)

therefore, GF = FH (corresponding angle)

6 0

3 years ago

Rewrite the function by completing the square. 4x^2-4x+1=0

andrey2020 [161]

Do in completing the square method.

${4x}^{2} - 4x + 1 = 0 \\ 4x^{2}-4x=-1 \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4} \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4} \\ x^{2}-x=\frac{-1}{4} \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2} \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4} \\ x^{2}-x+\frac{1}{4}=0 \\ \left(x-\frac{1}{2}\right)^{2}=0 \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}$

Now simplify.

$x-\frac{1}{2}=0 \\ x-\frac{1}{2}=0 \\ \\ \rightarrow \: x=\frac{1}{2} \\ \rightarrow \: x=\frac{1}{2}$

So, answer is..

$\boxed{x=\frac{1}{2} }$

Now rewrite the equation.

$4 x ^ { 2 } - 4 x + 1 = 0 \\ \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 }$

Verification :-

$4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-\frac{4}{2}+1=0 \\ 1-2+1=0 \\ -1+1=0 \\ \underline{ 0 = 0} \: \\ \dashrightarrow \text{true}$

3 0

3 years ago