Perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.
As given in the question,
Coordinates of vertices K(-2,1) and M(10,6)
KM = 
= 
= 13units
In equilateral triangle KL = LM = KM = 13 units
Perimeter of equilateral triangle KLM = 13 +13 +13
= 39 units
Therefore, perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.
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Answer:
1/3(5.2)h cm³
Step-by-step explanation:
A solid right pyramid has a regular hexagonal base with an area of 5.2 cm2 and a height of h cm. Which expression represents the volume of the pyramid?
One-fifth(5.2)h cm3 StartFraction 1 Over 5 h EndFraction(5.2)h cm3
One-third(5.2)h cm3 StartFraction 1 Over 3 h EndFraction(5.2)h cm3
Volume of the pyramid = 1/3 × area × height
Area = 5.2 cm²
Height = h cm
Volume of the pyramid = 1/3 × 5.2 cm² × h cm
= 1/3(5.2)h cm³
The cube root of 343 is 7.
One side has an area of 7*7 = 49 square cm
There are 6 sides to a cube
6 * 49 is the surface area = 294
ABC = 180-120=60
ACB = 180-(40+60)=80
Therefore ECD= 80 as ACB and ECD are vertically opposite angles
the solution is A as that is where the graphs intersect each other
