All categories

4 years ago

Which equation has a k-value of -5? A y=5x+3 B y=5x+5 C y=3x−5 D y=−5x

Mathematics

1 answer:

Veronika [31]4 years ago

7 0

Answer:

NANI!?5

Step-by-step explanation:

You might be interested in

Can someone help me im stuck

Tcecarenko [31]

Answer:

Step-by-step explanation:

5 0

3 years ago

The base diameter and the height of a cone are both

NeX [460]

Answer:

Step-by-step explanation:

volume of a cone is

V = ⅓πr²h

V = ⅓π(x/2)²x = ⅟₁₂πx³

3 0

3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

I need help on question 9 please!! Thank you!

jekas [21]

Answer:

Step-by-step explanation:

33000/0.27 =$8910

7 0

3 years ago

What does 5/12+23/10=

Serhud [2]

Answer:

PEMDAS

(5/12) +(23/10)

5/12=0.42

23/10=2.3

0.42+2.3=2.72

2.72 is the correct answer

4 0

4 years ago