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2 years ago

The graph below shows a probability distribution. The answer choices are below. Thanks! :)

Mathematics

2 answers:

Deffense [45]2 years ago

5 0

Answer:

it is p(3<x<4)

Step-by-step explanation:

tankabanditka [31]2 years ago

4 0

The 3rd one is correct

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Jeff gave 1/4 of a sum of money to his wife. Then he divided the remainder equally among his 4 children.

Semenov [28]

Answer:

A) The fraction of sum of money did each child receive is $\frac{3 x}{16}$

B) The sum of money did Jeff have $ 3200

Step-by-step explanation:

Given as :

Let The sum of money did Jeff have = $ x

The fraction of money did Jeff's wife get = $\frac{1}{4}$ of $ x

The remaining money Jeff will have = $ x - $\frac{1}{4}$ of $ x

I.e The remaining money Jeff will have = $\frac{4 x - x}{4}$

= $\frac{3 x}{4}$

A ) The remaining amount of money is divided equally among 4 children

So, The fraction of sum of money did each child receive = $\frac{\frac{3 x}{4}}{4}$

I.e The fraction of sum of money did each child receive = $\frac{3 x}{16}$

B ) If each child will receive $ 600

∴, $\frac{3 x}{16}$ = $ 600

Or, 3 x = $ 600 × 16

Or, 3 x = $ 9600

∴ x = $\frac{9600}{3}$

I.e x = $ 3200

So, The sum of money did Jeff have $ 3200

Hence ,

A) The fraction of sum of money did each child receive is $\frac{3 x}{16}$

B) The sum of money did Jeff have $ 3200 Answer

8 0

2 years ago

The Bishop's Peak 4-H club is having its annual fundraising dinner. Adults pay $35 apiece and children pay $25 apiece. If the nu

vodka [1.7K]

35a + 25c = 2660
a = 2c

35(2c) + 25c = 2660
70c + 25c = 2660
95c = 2660
c = 2660/95
c = 28 <=== there were 28 children tickets

a = 2c
a = 2(28)
a = 56 <== there were 56 adult tickets

4 0

2 years ago

Test again help please

netineya [11]

Answer:

4v+3 + 5v +6=180

ans is v=19

hope so its the ans

Step-by-step explanation:

mark as brainliest plzzz

4 0

2 years ago

Read 2 more answers

Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a

LekaFEV [45]

To make this a little clearer, let's give the pairs of inequalities the same denominator:

Question 1:
 $\frac{11}{15}$ ? $\frac{5}{7}$
First, apply the common denominator to the first fraction:
$(\frac{11}{15})7 \\ \frac{11}{15} * \frac{7}{7} \\ \frac{11*7}{15*7} \\ \frac{77}{105}$
Do the same for the second: $15( \frac{5}{7}) \\ \frac{5}{7}* \frac{15}{15} \\ \frac{5*15}{7*15} \\ \frac{75}{105}$
Nest, compare the two fractions:
$\frac{77}{105} \ \textgreater \ \frac{75}{105}$
Therefore:
$\frac{11}{15}$ > $\frac{5}{7}$

Question Two:
$\frac{5}{9}$ ? $\frac{7}{13}$
Apply the common denominator to fraction one:
$13( \frac{5}{9}) \\ \frac{5}{9} * \frac{13}{13} \\ \frac{5*13}{9*13} \\ \frac{65}{117}$
Fraction two:
$9(\frac{7}{13}) \\ \frac{7}{13} * \frac{9}{9} \\ \frac{7*9}{13*9} \\ \frac{63}{117}$
Evaluate:
$\frac{65}{117}$ > $\frac{63}{117}$
Therefore:
 $\frac{5}{9}$ > $\frac{7}{13}$

Hope this helps!

5 0

2 years ago

Nik and his friend bought shares of stock at the rate of $32 per share. For $3,520, Nik's friend bought 10 fewer shares than Nik

Svetradugi [14.3K]

Answer:

#1-List all outcomes for choosing the digit. *

A: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

B: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

C: 1, 2, 3, 4, 5, 6, 7, 8, 9

OD: a number

Both B and C

Step-by-step explanation:

7 0

2 years ago