How to solve the equation for the indicated variable: a-6[b-3(c-x)], for x.

4x+100 6x+216 find x

Lemur [1.5K]

Answer:

4x=100+6x=216=

Step-by-step explanation:

100+216=316 and 4x+6x= 10

316/10 = 31.6

6 0

3 years ago

The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V equals t

Jobisdone [24]

Answer:

20.3 ft/sec

Step-by-step explanation:

7 0

3 years ago

Which of the following complete the proof above?

svp [43]

Answer:

(A)

Step-by-step explanation:

To be honest, since all of them are different, as long as you get the first one right, you will get the others right. A is your answer, for the following reasons:

Reflexive Property: The Reflexive property states that the mirrored version of itself will always be congruent with itself. Generally, to make it easier, they will write it opposite (as they did in the given proof):

<em>line</em> AC ≅ <em>line</em> CA

~

8 0

3 years ago

Read 2 more answers

All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessarily the same as the weigh

BaLLatris [955]

Answer:

The largest possible weight of flour is 11.25 pounds.

Step-by-step explanation:

To start with, we will assume that the weight of 1 sack of sugar = x pounds

We will also assume that the weight of 1 sack of flour = y pounds

So, the weight of 2 sacks of sugar = 2 * (x) = 2x

Same thing goes for the weight of 3 sacks of flour = 3 * (y) = 3y

Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds

= 2x + 3y ≤ 40............ we'll call that equation 1.

Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds

= y ≤ 2x + 5........................ we'll call that equation 2

Therefore, we'll solve for the values of x and y in the two equations and we will get:

2x + 3y ≤ 40

y ≤ 2x + 5

Now, substitute the value of y into equation 1

2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40

⇒ 2x + 6x + 15= 40

⇒ 8x + 15 = 40

⇒ 8x = 25

⇒ x = 25/8

⇒ x = 3.12

x cannot be more than 3.12 pounds, so we solve for y

Putting the value of x into equation 2, we'll get

⇒ 2y + 5 = 2(3.12) + 5

⇒ y = 11.25 pounds.

So, n cannot be more than 11.25 pounds

8 0

3 years ago

What is the mass of an object that has a density of 1.3 g/cm3 and a volume

tangare [24]

Answer:

The mass of the object is 2.6 grams

Step-by-step explanation:

The density of an object is the ratio between its mass and its volume

The equation of the is d = $\frac{m}{V}$ , where

m is the mass

V is the volume

Let us use this equation to solve the question

∵ An object has a density of 1.3 g/cm³

∴ d = 1.3 g/cm³

∵ Its volume is 2 cm³

∴ V = 2 cm³

→ Substitute them in the equation of the denisty above

∵ 1.3 = $\frac{m}{2}$

→ Multiply both sides by 2

∴ 2 × 1.3 = 2 × $\frac{m}{2}$

∴ 2.6 = m

∴ The mass of the object is 2.6 grams

8 0

2 years ago