Answer:
I think the answer is D.) 7/8 mile
Step-by-step explanation:
If you make the mixed numbers improper fractions, 2 and 1/8 is 17/8, 1 and 1/4 (2/8) is 10/8, then you subtract the numerators and keep the denomitators the same to get 7/8 mile (sorry if I spelt something wrong)
A function can be represented by equations and tables
- 4 users are logged in by 9am
- The domain is [3,23] and the range of the function is [3,4]
<h3>The number of users at 9am</h3>
The function is given as:
At 9am, x = 9.
So, we have:
Simplify
Approximate
Hence, 4 users are logged in by 9am
<h3>The domain</h3>
Set the radical to 0
Solve for x
The maximum time after midnight is 23 hours.
So, the domain is [3,23]
<h3>The range</h3>
When x = 3, we have:
When x = 23, we have:
So, the range of the function is [3,4]
Read more about domain and range at:
brainly.com/question/2264373
Answer:
Step-by-step explanation:
Answer: The numbers are: " 21 " and " 105 " .
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Explanation:
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Let "x" be the "one positive number:
Let "y" be the "[an]othyer number".
x = 1/5 (y)
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Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".
So, y − x = 84 .
Add "x" to each side of this equation; to solve for "y" in terms of "x" ;
y − x + x = 84 + x ;
y = 84 + x ;
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So, we have:
x = (1/5) y ;
and: y = 84 + x ;
Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;
y = 84 + [ (1/5)y ]
Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;
y − [ (1/5)y ] = 84 + [ (1/5)y ] − [ (1/5)y ] ;
to get:
[ (4/5)y ] = 84 ;
↔ (4y) / 5 = 84 ;
→ 4y = 5 * 84 ;
Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;
4y / 4 = (5 * 84) / 4 ;
y = 5 * (84/4) = 5 * 21 = 105 .
y = 105 .
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Now, plug "105" for "y" into:
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Either:
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x = (1/5) y ;
OR:
y = 84 + x ;
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to solve for "x" ;
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Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
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Start with:
x = (1/5)y
→ (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;
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So, x = 21; y = 105 .
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Now, let us see if this values hold true in the other equation:
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y = 84 + x ;
105 = ? 84 + 21 ?
105 = ? 105 ? Yes!
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The numbers are: " 21 " and "105 " .
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Answer: ( Min = 0 , , , , Max = 10 )
Step-by-step explanation:
Given : A random sample of 11 days were selected from last year's records maintained by the maternity ward in a local hospital, and the number of babies born each day of the days is given below:
3 7 7 10 0 7 1 2 5 3 0
We first arrange them in increasing order , we get
0 0 1 2 3 3 5 7 7 7 10
Here , N= 11
Now , we can see that
Minimum value = 0
Maximum value = 10
First quartile =
Second quartile = Median = Middlemost number = 3
Third quartile =
∴ The required five number summary : ( Min = 0 , , , , Max = 10 )