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3 years ago

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Can you always use synthetic division for dividing polynomial? Please explain

1 answer:

shtirl [24]3 years ago

5 0

No, you can only use synthetic division if you're dividing by something that looks like this:
x+b.

If the polynomial you're dividing by looks like this (for example):
2x+1
or this:
2x^2 + x + 1

(these are all made up numbers, by the way, just examples)

then you cannot divide by it and muse therefore use long division

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melamori03 [73]

I don’t think you should be cheating, Grayden

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LAST QUESTION, FINALLY OMG. This confused me.

Inessa [10]

Answer:house, furniture, cash, savings,clothes are assets. Car loan, boat payoff, credit card debt, student loans are liabilities, 48275 is total liability, 90585 is total assets, 42310 it net worth

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(1 point) Use the graph below to find exact values of the indicated derivatives, or state that they do not exist. If a derivativ

svetlana [45]

Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

$\mathbf{h(x) = f(g(x))}$

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The slopes of f(x) are: 3/2 and -3/2

So, the equations are:

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$\mathbf{f(x) = -\frac{3}{2}x,\ x \ge 2}$

<u>Graph g(x)</u>

The slope of g(x) is: -1/2

So, the equation is:

$\mathbf{g(x) = -\frac 12x}$

<u>For x = 1 and x = 2, we have:</u>

So, we have:

$\mathbf{h(x) = f(g(x))}$

Where:

$\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2}$ and $\mathbf{g(x) = -\frac 12x}$

$\mathbf{h(x) = f(g(x))}$ becomes

$\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}$

Open brackets

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$\mathbf{h'(x) = -\frac{3}{4}}$

So:

$\mathbf{h'(1) = -\frac{3}{4}}$

$\mathbf{h'(2) = -\frac{3}{4}}$

For x = 3, we have:

$\mathbf{h(x) = f(g(x))}$

Where:

$\mathbf{f(x) = -\frac{3}{2}x\ x \ge 2}$ and $\mathbf{g(x) = -\frac 12x}$

$\mathbf{h(x) = f(g(x))}$ becomes

$\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}$

$\mathbf{h(x) = \frac{3}{4}x}$

Differentiate

$\mathbf{h'(x) = \frac{3}{4}}$

Substitute 3 for x

$\mathbf{h'(3) = \frac{3}{4}}$

Hence, the values of the derivatives are:

$\mathbf{h'(1) = -\frac{3}{4}}$ , $\mathbf{h'(2) = -\frac{3}{4}}$ and $\mathbf{h'(3) = \frac{3}{4}}$

Read more about graphed functions at:

brainly.com/question/11804653

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Kathryn’s total assets are $57,219. Her total liabilities are $43,244. What is her net worth? A. $14,198 B. $1397 C. $13,975 D.

zepelin [54]

If your going to add then it would be
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I your going to subtract then it would be
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ello

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3 years ago