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Basile [38]
3 years ago
8

Make x the subject y=ab-x

Mathematics
2 answers:
sergejj [24]3 years ago
6 0

Answer:

x = ab - y

Step-by-step explanation:

y - ab = -x

-y + ab = x

can also be written as

x = ab - y

lord [1]3 years ago
6 0

Answer:

x=ab-y

Step-by-step explanation:

y=ab-x

move y to where x is and move x to where y is and when you move them their signs will change

x=ab-y

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How to solve this equation 18.5 = -4.5 + 7(k + 6)
yawa3891 [41]
1. Add -4.5 to 18.5
2. Divide 23 by 7
3. Then subtract 6 from -2.7
8 0
3 years ago
Read 2 more answers
Can someone please help me
Evgesh-ka [11]

Answer:

UW ≈ 6.55 ≈ 7

Step-by-step explanation:

cos (35) = adjacent/hypotenuse

cos(35) = UW/VW

cos(35) = UW/8

8*cos(35) = UW

UW ≈ 6.55

Hope this helped! <3

7 0
3 years ago
A rectangle and a square have the same area. a. The width of the rectangle is w inches. The length of the rectangle is 15 inches
harkovskaia [24]

9514 1404 393

Answer:

  a) w(4w-15)

  b) w²

  c) w(4w -15) = w²

  d) w = 5

  e) 5 by 5

Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

  A = w(4w -15)

__

b) If w is the side length, the area of the square is (also) the product of length and width:

  A = w²

__

c) Equating the expressions for area, we have ...

  w(4w -15) = w²

__

d) we can subtract the right side to get ...

  4w² -15w -w² = 0

  3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

__

e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

4 0
3 years ago
Match each expression written in standard form to the equivalent expression in factored form
den301095 [7]

Answer:

1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)

4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)

Step-by-step explanation:

To obtain the answer to the question, first let us factorise each expression. This is illustrated below:

1. 15x^7y^2 + 4x^3

Common factor is x^3, therefore the expression is written as:

x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x

Common factor is 3x, therefore the expression is written as:

3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy

Common factor is 3xy, therefore the expression is written as:

3xy(5x^6y + 2)

4. 15x^7 + 10y^2

Common factor is 5, therefore the expression can be written as:

5(3x^7 + 2y^2)

4 0
3 years ago
Jason has 48 muffins, which he needs to box up into dozens. How many boxes does he need?
Olegator [25]
He needs 4 boxes :)
Dozen= 12
48 ÷12=4
8 0
2 years ago
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