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mariarad [96]
3 years ago
10

Solve the inequality 5(2h+8)<60

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

Answer and Step-by-step explanation:

Greetings!

Let's~answer~your~question!

First, ~let's~ work~ on ~the~ left~ hand ~side~ of ~your ~inequality,~ the~ 5(2h+8)~This\\ means,~ for~ instance, ~to ~see ~if ~it ~can~ be ~simplified ~at~ all.~Multiply~ h ~and~ 2

The~ answer~ is~ h

2\times h~ evaluates~ to~ 2h

2\times h+8 ~evaluates~ to~ 2h+8

Multiply ~5~ by~ 2h+8

we ~multiply~ 5~ by~ each ~term ~in~ 2h+8 ~term ~by~ term~and~we~use~distributive~\\property.

Multiply ~5 ~and~ 2h

5\times2h=10h

Multiply~ 5 ~and ~8

5 \times 8 = 40

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I NEED HELP WITH QUESTION PLEASE!!<br> What is the inverse of f(x)<br> (x) = (x-4)² for x ≥ 4?
goblinko [34]

Answer:

4th choice \bold{f^{-1}(x) = \sqrt{x} + 4}

Step-by-step explanation:

<u>Definition of the inverse of a function</u>

A function g is the inverse of a function f if whenever y=f(x) then x=g(y). In other words, applying f and then g is the same thing as doing nothing. We can write this in terms of the composition of f and g as g(f(x))=x. The domain of f becomes the range of g and the range of f becomes the domain of g

To solve for the inverse of the function f(x) =\left(x-4\right)^2

Let y=\left(x-4\right)^2

\mathrm{Replace}\:x\:\mathrm{with}\:y \text{ and replace }\:y\:\mathrm{with}\:x

x=\left(y-4\right)^2

Switch sides
\left(y-4\right)^2=x

Take square roots on both sides
y-4=\pm\sqrt{x}

Add 4 on both sides to solve for y

y = \pm\sqrt{x} + 4

We have two solutions

y=\sqrt{x}+4,\:y=-\sqrt{x}+4

To determine which one of these to be chosen not that in the given choices we can eliminate the first two since x cannot be negative

The third choice can also be eliminated since
-\sqrt{x} + 4 is a decreasing function for x \ge 0

So the last answer choice is correct and the inverse off(x) = (x-4)^2

is given by  f^{-1}(x) = \sqrt{x} + 4

Answer:4th choice \bold{f^{-1}(x) = \sqrt{x} + 4}

Note

Domain of  (x-4)² is [4, ∞) since x ≥ 4 and (x-4)²  cannot be negative

Range of (x-4)²  is [0,  ∞)

Domain of \sqrt{x}\:+\:4 is [0, ∞)

Range of \sqrt{x}\:+\:4 is [4, ∞)

so indeed the domain of (x-4)² has become the range of \sqrt{x}\:+\:4 and the range of (x-4)² has become the domain of \sqrt{x}\:+\:4

5 0
1 year ago
Mrs. Smith gave two classes the same quiz. She randomly selected 5 students from each class to compare the classes. The scores o
Tasya [4]

The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.

<h3>How to calculate the mean?</h3>

We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A  and the range of class B is also less then the class A.

It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.

In this case, the computation will be:

Class A: Mean = 422/5= 84.4.

Range: 94-74 = 20

Class B: Mean = 418/5 = 83.6.

Range= 88-80 = 8

Learn more about mean on:

brainly.com/question/1136789

#SPJ1

4 0
2 years ago
the mean sale per customer for 40 customers at a grocery store is $23.00, with a standard deviation of $6.00. Apply Chebyshev's
Lunna [17]
The answers is 75%x40=0.75x40=30
7 0
3 years ago
Write the number in two orher forms 314,207
asambeis [7]
Word Form: Three hundred fourteen thousand two hundred seven

Expanded Form: 300,000 + 10,000 + 4,000 + 200 + 7
5 0
3 years ago
Read 2 more answers
3.) What is the diameter and circumference of a circle given the area is 16
denis-greek [22]

Answer:

D =4.51 and the

Area is=16

7 0
3 years ago
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