Answer:
Solution given:
In right angled triangle
ABC.
with respect to <C=40°
opposite side=AB
adjacent=BC=DE=30ft
now
relationship between opposite side and adjacent
is given by tan angle
tan 40°=oppo/adjacent
tan40°=AB/30
AB=tan40*30
AB=25.2
<u>Now</u><u> </u>
<u>height</u><u> </u><u>of</u><u> </u><u>flagpole</u><u> </u><u>=</u><u>AB</u><u>+</u><u>BE</u><u>=</u><u>2</u><u>5</u><u>.</u><u>2</u><u>+</u><u>5</u><u>=</u><u>3</u><u>0</u><u>.</u><u>2</u><u>f</u><u>t</u>
<u>option</u><u> </u><u>4</u><u>t</u><u>h</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>
To find The largest number of gift bags that can be packed, you will need to find the biggest way all three of these numbers can be divided evenly. You can find this answer by finding the greatest common factor.
I will show this by listing the prime factorization's for each number, and then we will look for all the common factors.
171 = 3 x 3 x 19
63 = 3 x 3 x 7
27 = 3 x 3 x 3
All three lists share two 3s. The means that the biggest way they could be divided is into nine bags (3 x 3).
(F*g) means f ( g(x) ) . Knowing this we can say
F(g(x)) = 3(5-x) ^2
= 3 (5-x)(5-x)
=
no 1. is a
no 2. is none of the above
