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olga55 [171]
3 years ago
14

Display the set of data in a histogram.

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

The answer to your question is the third histogram

Step-by-step explanation:

What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.

The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.

Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.

The third histogram is correct because all the bars are in agreement with their frequencies.

The last histogram is incorrect, for example, the last frequency is 12, not 3.

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Find the value of x.<br> If necessary, you may learn what the markings on a figure indicate.<br> 74°
marissa [1.9K]

Answer:

x = 61

Step-by-step explanation:

Left hand triangle containing 1 angle of 74

Label the other angle opposite the marked side also as 74

Find the third angle. Call it y.

y + 74 + 74 = 180           Combine like terms

y + 148 = 180                 Subtract 148 from both sides.

y = 180 - 148

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=============

Now work with the triangle on the right.

label the angle making up the right angle = z

32 + z = 90                             These two angles are complementary = 90

32 - 32 + z = 90 - 32              Subtract 32 from both sides

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x + x + z = 180                         Substitute

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3 years ago
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A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
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Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

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∵ The volume = 150 cm³

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# The density of mercury is 13.6 g/cm³ at 23 C°

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∵ Density = mass/volume

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∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
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