1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina CMI [18]
4 years ago
7

The elevation of Mt. Everest is 29,028 feet. The elevation of the Dead Sea is –485 feet. What is the difference in the elevation

between Mt. Everest and the Dead Sea?
Mathematics
2 answers:
navik [9.2K]4 years ago
6 0

Answer:

28,543

Step-by-step explanation:

If we take the height of Mt. Everest (29,028) and the height of the Dead sea (-485) and subtract we get the `answer of 28,543.

swat324 years ago
4 0

Answer:

29,513

Step-by-step explanation:

You might be interested in
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
24 is equal to 3 more than the product of 7 and number
Lostsunrise [7]

24 = 7x + 3

7x = 21

21/7 = 3, so:

x = 3

The number is 3

7 0
3 years ago
What is the length of the hypotenuse of the triangle when x=13
ValentinkaMS [17]

Answer:

90.80

Step-by-step explanation:

6x+4

= (6)(13)+4

= 78+4

=82

3x

=(3)(13)

= 39

So we know the sides are 39 and 82

Pythagoras theorem in triangles

= a2+b2= c2

Now, we know the value of a and B but not c (the hypotenuse)

Therefore,

c2 = (39)^2 + (82)^2

= 1521+ 6724

= 8245

so, c = √8245

= 90.80 unitd

7 0
3 years ago
Describe TWO factors that have impacted the evolution of American education. Make sure to analyze how this factor has impacted t
yan [13]
Cigar buzzing some ah rustic pick gn flick so stop rn
3 0
3 years ago
What is 4 3/4 - 1/3 = in fraction form
pentagon [3]

Answer:

53/12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • How many lines of symmetry does the figure of the heart below appear to have
    13·2 answers
  • Distributive property for <br> 14x+21y+7z
    7·1 answer
  • Alexis is making a cake and needs 4/5 cups of brown sugar for every 3/4 pounds of flour. How much brown sugar will be needed for
    11·1 answer
  • What is the answer to this expression?
    6·1 answer
  • Less expensive and cleaner than power plants that use fossil fuels, why are they not used on a larger scale?
    9·2 answers
  • 2 out of 3 dogs weigh less than 20 pounds. What is the decimal equivalent for the number of dogs weighing under 20 pounds
    12·1 answer
  • Chelsea spent $26 on a magazine and some notepads. If the magazine cost $2 and each notepad cost $4, then how many notepads did
    14·2 answers
  • . A marine biologist needs to add a new chemical to one of her fish tanks (300 L in volume). She adds a chemical solution with c
    14·1 answer
  • What number line is the right one?? HELP
    12·1 answer
  • Marking as brainliest, if u answer this an comment ur inst
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!