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3 years ago

Cassie has test grades of 71, 78 and 83 on the first three tests in her

Mathematics

2 answers:

Neporo4naja [7]3 years ago

3 0

Answer:

x ≥ 88

Step-by-step explanation:

In order to have at least an average of 80 after 4 tests, the sum of her scores must be at least 80 * 4 = 320 so we can write the following inequality:

71 + 78 + 83 + x ≥ 320

232 + x ≥ 320

x ≥ 88

Sphinxa [80]3 years ago

3 0

Answer:

Your correct answer to this problem is x ≥ 88

Step-by-step explanation:

71 + 78 + 83 + x ≥ 320

232 + x ≥ 320

= x ≥ 88

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Simplify negative 5 minus the square root of negative 44 negative 5 minus 4 times the square root of 11 i negative 5 minus 4 i t

Anika [276]

Answer:

$-5-\sqrt{-44}=-5-2\sqrt{11}i$

Step-by-step explanation:

We want to simplify:

$-5-\sqrt{-44}$

We rewrite the expression under the radical sign to obtain:

$-5-\sqrt{4\times11\times -1}$

We split the expression under the radical sign to get:

$-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}$

Recall that:

$\sqrt{-1}=i$

This implies that:

$-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}=-5-2\sqrt{11}i$

Therefore $-5-\sqrt{-44}=-5-2\sqrt{11}i$

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3 years ago

FIND THE AREA OF THE FIGURE BELOW

Romashka [77]

Answer:

220 squared units

Step-by-step explanation:

first, find the area of the rectangle by multiplying 8 by 20. Then, fin the area of the triangle by multiplying 6 by 20 and then dividing the result by 2.

8*20=160

6*20=120

120/2=60

Finally, add them together and you get 220 units squared.

7 0

2 years ago

If x = 10 and the area of the rectangle is 120, what is the length of the other side?

sweet [91]

Answer:

Step-by-step explanation:

to find area you do length times width. if we have one side we have to find what 120/10 is. that is 12. 10 x 12 is 120.

6 0

3 years ago

G(x)=2x-2 <br> f(x)=x^2+3x <br> find (g of f)(2+x)

Bumek [7]

Answer:

Step-by-step explanation:

G(f(2+x))=g(2+x)^2+3(2+x)=2(2+x)^2+3(2+x)-2=2(4+4x+x^2)+6+3x=8+8x+2x^2+6+3x=2x^2+11x+14

6 0

3 years ago

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

gavmur [86]

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

Learn more details about integer here:

brainly.com/question/15276410

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4 0

1 year ago