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3 years ago

10

PLEASE HELP ME!!!!!!!!!

1 answer:

NemiM [27]3 years ago

8 0

The answer is “The speed of a car increases Constantly by 10 miles” and “The radioactivity of a substance decreases by 10 every year” last one is “ The amount of money in an account decreases for a few months and then increases”

Hope that helped! :)

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Equation 1: m = 8 + 2n

slava [35]

Answer:

1:×4

m×4=(8+2n)×4

4m=32+8n

now,

1:×4 - 2:

4m-4m = 32+8n -4+4n

0=(32-4) +(8n-4n)

0=28+4n

28=-4n

n= -7

n=-7. 1:,

m=8+2n

m=8+2×(-7)

m=8-14

m=-6

7 0

2 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago

1.5 times the amount a bucket holds makes 6 gallons. How many gallons does the bucket

ira [324]

Answer:

1.5x = 6

Step-by-step explanation:

This represents 1.5 times the amounts a bucket holds. (I'm assuming you mean x when you typed z)

3 0

2 years ago

Student Council sells bottled water at the cheerleading completion. At this rate, how many cases of bottled water would they sel

amid [387]

Answer:

27

Step-by-step explanation:

Lets find the rate of selling:

Let v= the rate of selling, b = number of bottles of water, and t = time:

b over t gives us the $v=\frac{b}{t}=\frac{3}{20}=\frac{6}{40}=0.15$ rate of selling:

3 hours is 60min * 3 = 180 mins, and since v=b/t, vt=b:

(0.15) * 180 = 27 bottles of water

4 0

2 years ago

Find the slope of a line with points: ( -5 , -8 ) and ( 6 , -3 )

Natasha_Volkova [10]

(y2-y1)/(x2-x1) (-3 - (-8))/(6- (-5))= 5/11

6 0

3 years ago