All categories

3 years ago

I’ve got a couple trigonometry questions that I really need help on. I don’t understand them at all.

Mathematics

1 answer:

wel3 years ago

5 0

Answer:

Q5. Option 1

Q7. Option 4

Step-by-step explanation:

Please see the attached pictures for full solution.

You might be interested in

Solve for x x/2-8=17

lisabon 2012 [21]

x/2-8=17

add 8 to both sides

x/2 = 25

multiply both sides by 2

x = 50

8 0

3 years ago

What is the area of this triangle 12 m 13 m and 5 m is the measurements of the triangle

VashaNatasha [74]

Answer:

30 m^2.

Step-by-step explanation:

This is a right-angled triangle because it obeys the Pythagoras theorem

( 13^2 = 12^2 + 5^2).

So its area = 1/2 * base * height

= 1/2 * 5 * 12

= 30 m^2

7 0

3 years ago

12) As of August, 2011, Russia has had 21 rocket launch failures out of 743 total launches. To the nearest whole number, how man

bogdanovich [222]

Answer:

Step-by-step explanation:

It is given that, in Russia there are 21 rocket launch failures out of 743 total launches. We need to find no of failures for the next 800 launches.

21 rocket = 743 launches

1 launch = $\dfrac{21}{743}\ \text{failures}$

For 800 launches,

$=\dfrac{21}{743}\ \text{failures}\times 800\\\\=22.611\ \text{failures}$

= 23 failures

So, there are 23 failures in next 800 launches.

5 0

3 years ago

Which graph shows the solution to the system of linear inequalities? y< 2x-5 y>-3x + 1

trapecia [35]

Answer:

See explanation

Step-by-step explanation:

Plot the solution sets to both inequalities.

1. For the inequality $y$ First, plot the dotted line $y=2x+5$ (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

$2\cdot 0-5=-5$

so the origin does not belong to the needed part. Shade the part, which does not include origin.

2. For the inequality $y>-3x+1.$ First, plot the dotted line $y=-3x+1$ (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.