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3 years ago

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (g•h)(5)?

Mathematics

2 answers:

maks197457 [2]3 years ago

4 0

Answer:

Step-by-step explanation:

timofeeve [1]3 years ago

3 0

Answer:

(g · h)(5) = -50

Step-by-step explanation:

Step 1: Define

h(x) = x - 7

g(x) = x²

Step 2: Find (g · h)(x)

(g · h)(x) = x²(x - 7)

(g · h)(x) = x³ - 7x²

Step 3: Find (g · h)(5)

(g · h)(5) = 5³ - 7(5)²

(g · h)(5) = 125 - 7(25)

(g · h)(5) = 125 - 175

(g · h)(5) = -50

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3 years ago

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scZoUnD [109]

The amount of water decreases $16\frac{1}{2}$ pints in 12 weeks.

Solution:

The amount of water decreases in 7 weeks = $9\frac{5}{8}$ pints

The amount of water decreases each week is same.

Let us first change the mixed fraction into improper fraction.

$9\frac{5}{8}$ pints = $\frac{(9\times8)+5}{8}$

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$$=\frac{\frac{77}{8} }{7}$

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3 years ago

A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe

Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

$\omega=\frac{v}{r}$ ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

$47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}$

next, you replace the values of v and r in the equation (1):

$\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}$

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

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3 years ago

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Answer:

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1 year ago