Question

Find the required measurements of the following trapezoids. b1 = 12 cm b2 = 16 cm h = 9 cm. Compute the area. ? cm2

Answer 1

Answer:

$126\text{ cm}^2$

Step-by-step explanation:

Since we know that the area of trapezoid is one-half the sum of parallel sides times height of trapezoid.

$\text{Area of trapezoid}=\frac{1}{2}*\text{The sum of length of parallel sides *Height}$

$\text{Area of trapezoid}=\frac{1}{2}*(b_1+b_2)*h$

$\text{Area of trapezoid}=\frac{1}{2}*(12+16)*9$

$\text{Area of trapezoid}=\frac{1}{2}*(28)*9$

$\text{Area of trapezoid}=14*9$

$\text{Area of trapezoid}=126$

Therefore, the area of our given trapezoid will be 126 square cm.

Answer 2

Area= (b1+b2)/h
= (12+16)/9
= 28/9 = 3.111