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3 years ago

Find the surface area of the cylinder in terms of pi. 9cm and 19cm

Mathematics

1 answer:

Natali [406]3 years ago

3 0

Answer:

Surface area of cylinder= 211.5π

Step-by-step explanation:

Given,

Height of cylinder = 19cm

Diameter of cylinder = 9cm

i.e Radius of cylinder = diameter/2 = 9/2 = 4.5cm

Surface area of cylinder = 2πrh + 2πr²

Plug corresponding values of r and h in surface are formula.

Surface area of cylinder = 2πrh + 2πr² = 2π*4.5*19 + 2π*4.5²

Surface area of cylinder = 171π+40.5π = 211.5π

Hence we get surface area of cylinder= 211.5π

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Answer:

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$H_0: \mu = 2.5$

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$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}$

$z = 1.7$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, is of $z^{\ast} = 1.645$