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fredd [130]
3 years ago
11

Consider this square pyramid. Recall the volume can be found using the formula V = 1/3Bh.

Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

Option A.) 16 m³. The volume of the new pyramid is the volume of the original pyramid times 1/64.

Step-by-step explanation:

step 1

Find the volume of the original pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}Bh

where

B is the area of the base

h is the height of the pyramid

we have

B=16^{2}=256\ m^{2} ----> is the area of a square

h=12\ m

substitute

V=\frac{1}{3}(256)(12)

V=1,024\ m^{3}

step 2

Find the volume of the new pyramid

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

so

Let

z -------> the scale factor

x ------> the volume of the new pyramid

y -----> the volume of the original pyramid

z^{3}=\frac{x}{y}

we have

z=\frac{1}{4}

y=1,024\ m^{3}

substitute and solve for x

(\frac{1}{4})^{3}=\frac{x}{1,024}

x=(1,024)\frac{1}{64}=16\ m^{3}

therefore

The volume of the new pyramid is the volume of the original pyramid times 1/64

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Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

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