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Yakvenalex [24]
3 years ago
14

a student measures a sample of mass and volume! How can the student use this information to identify the sample!

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0
Hola no que no me ha dicho nada de la policía ‍♀️ que no me han dicho nada de la policía y han dado la vuelta y a los dos de que me han dicho
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Pls help me with #7!! i don’t understand
GREYUIT [131]
The correct answer is b lave flows from a volcano and piles up
4 0
3 years ago
If a card is picked at random from a standard 52-card deck, what is the probability of getting a spade or a 8
g100num [7]

Answer:

1/4, 25%, or 0.25

Step-by-step explanation:

Therefore, as each suit contains 13 cards, and the deck is split up into 4 suits, that leaves us with a 13/52 chance to pick a spade.

That fraction is equivalent to 1/4, so that leaves us with a probability of picking a spade at:

1/4, 25%, or 0.25

8 0
3 years ago
(-2.8)^6 (Round to three decimal places as needed)
vladimir2022 [97]
-2.8 • -2.8 • -2.8 • -2.8 • -2.8 • -2.8
=481.890
7 0
4 years ago
Read 2 more answers
Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.
Keith_Richards [23]
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0
3 years ago
What is the frequency of yellow
Zina [86]

Answer:

5.131 × 10¹⁴  Hz

Step-by-step explanation:

<u>Planck relation</u>

\large\boxed{E = hf}

where:

  • E = Energy of the photon (J).
  • h = Planck's constant (J · s).
  • f = frequency of light produced (Hz).

Given values:

  • E = 3.4 × 10⁻¹⁹ J
  • h = 6.626 × 10⁻³⁴ J · s

Substitute the given values into the formula and solve for f:

\implies 3.4 \times 10^{-19}=(6.626 \times 10^{-34})f

\implies f=\dfrac{3.4 \times 10^{-19}}{6.626 \times 10^{-34}}

\implies f=\dfrac{3.4}{6.626} \times \dfrac{10^{-19}}{10^{-34}}

\implies f=0.5131\times 10^{(-19-(-34))}

\implies f=0.5131 \times 10^{15}

\implies f=5.131 \times 10^{14}

8 0
1 year ago
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