Answer:
There are vertical asymptotes at x: {-1, 0, 5}
Step-by-step explanation:
It's easier (at least for some) if you write this function as
3
F(X) = ------------------
x(x-5)(x+1)
Can you now see that if x = 0, this function is undefined? Same for x = 5 and x = -1? There are vertical asymptotes at x: {-1, 0, 5}
Can you show a clearer picture ??
Answer:
1) 5 2) 6 3) 1.25 or -1.75
Step-by-step explanation:
1. x^2 - 25 = 0
x^2 - 25 = 0
First, add 25 to both sides!
x^2 = 25
Now square root both sides.
x = 5
2. (x-2)^2 = 16
First, square root both sides.
(x-2) = 4
Add 2 on both sides.
(x) = 6
x = 6
3. Quadratic Formula = -b ±
/ 2a
Substitute in:
-6 ±
/ 2(2)
-6±
/ 4
Both forms:
-6 +
/ 4
5 / 4 = 1.25
Negative:
-6 - 1 / 4
-7 / 4 = -1.75
It’s is 6 because I added it all up and all you have to do is division
81473478 is the correct answer
hope this helped